
This method retrieves the currently selected file(s)' path name.
Returns the following according to the situation:
The recommended convention is passing the control identifier directly:
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(Odcl_FileDlg_GetPathName MyControlReference [as Reference] ) |
An alternative convention is to identify the control by providing the project file, the dialog name and the control name:
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(Odcl_FileDlg_GetPathName ProjectFile [as String] DialogName [as String] ControlName [as String] ) |
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; Get the path name (setq rValue (Odcl_FileDlg_GetPathName MyProject_MyForm_MyControl)) |