
This method retrieves the current file selection list.
Returns the following according to the situation:
The recommended convention is passing the control identifier directly:
Copy Code |
|---|
(Odcl_FileDlg_GetFileNameList MyControlReference [as Reference] ) |
An alternative convention is to identify the control by providing the project file, the dialog name and the control name:
Copy Code |
|---|
(Odcl_FileDlg_GetFileNameList ProjectFile [as String] DialogName [as String] ControlName [as String] ) |
Copy Code |
|---|
; Get the selected files (setq rValue (Odcl_FileDlg_GetFileNameList MyProject_MyForm_MyControl)) |