
This method will retrieve the type of file indicated.
Returns the following according to the situation:
The recommended convention is passing the control identifier directly:
Copy Code |
|---|
(Odcl_DwgList_GetType MyControlReference [as Reference] nIndex [as Integer]) |
An alternative convention is to identify the control by providing the project file, the dialog name and the control name:
Copy Code |
|---|
(Odcl_DwgList_GetType ProjectFile [as String] DialogName [as String] ControlName [as String] nIndex [as Integer]) |
Copy Code |
|---|
; Check if the third entry is a directory (setq rValue (Odcl_DwgList_GetType MyProject_MyForm_MyControl 2)) |