
This method will retrieve the full file name of the currently select file or directory.
Returns the following according to the situation:
The recommended convention is passing the control identifier directly:
Copy Code |
|---|
(Odcl_DwgList_GetFileName MyControlReference [as Reference]) |
An alternative convention is to identify the control by providing the project file, the dialog name and the control name:
Copy Code |
|---|
(Odcl_DwgList_GetFileName ProjectFile [as String] DialogName [as String] ControlName [as String]) |
Copy Code |
|---|
; Get the file path of the current selection (setq rValue (Odcl_DwgList_GetFileName MyProject_MyForm_MyControl)) |